java数组反转

/**
* 1,数组的类型不定
* 2,个数不定
**/
import java.lang.reflect.Array;

public class ArrayUtils{

public static void main(String[] args) {
int[] myarray = {1, 2, 3};

int[] newarray = invertArray(myarray);

for (int i = 0; i < newarray.length; i++) {
System.out.println(newarray[i]);
}
}

/**
* 反转数组
*
*/
public static <T> T invertArray(T array) {
int len = Array.getLength(array);

Class<?> classz = array.getClass().getComponentType();

Object dest = Array.newInstance(classz, len);

System.arraycopy(array, 0, dest, 0, len);

Object temp;

for (int i = 0; i < (len / 2); i++) {
temp = Array.get(dest, i);
Array.set(dest, i, Array.get(dest, len - i - 1));
Array.set(dest, len - i - 1, temp);
}

return (T)dest;
}
}

评论

2 楼 futily 2014-05-18  

public static void middleReverseArray(Object[] obj) {
Object tmp = null;
if (obj.length % 2 == 0) {
for (int i = 1; i < (obj.length / 2); i++) {
tmp = obj[i - 1];
obj[i - 1] = obj[obj.length / 2 + i - 1];
obj[obj.length / 2 + i - 1] = tmp;
}
} else {
for (int i = 1; i <= (obj.length / 2); i++) {
tmp = obj[i - 1];
obj[i - 1] = obj[obj.length / 2 + i];
obj[obj.length / 2 + i] = tmp;
}
}
}

1 楼 futily 2014-05-14  

平xiong，我已经搞定，因为XXXX原因代码我回去后重新贴到你这里